#include <iostream>
#include <string>
#include <cmath>
using namespace std;

void print(int *i)
// Print the memory address of what i points to
{
  cout << i << endl;
}

void print2(int *i)
// Print to screen  the value of what i points to
{
   cout << (*i) << endl;
}

struct tdcoord { int x, y; };

float distanceFromOrigin(tdcoord *c)
// Return distance from origin ( sqrt(x*x+y*y) ) for // coordinate c. Use the -> operator in all accesses to the
// struct.

{
   float distance = sqrt(c->x*c->x+c->y*c->y);
   return distance;

   // is equivalent to:
   return sqrt(c->x*c->x+c->y*c->y);
}

int sum(int *a, int s)
// returns the sum of the array a which is of size s

{
  int sum = 0;
  int i;
  for (i=0;i<s;i++) 
    sum+=a[i]; // sum = sum + a[i];
  return sum;
}

int* reverse(const int a[], int s)
// Allocate a new array of size s, and copy the contents of 
// a into the new array in REVERSE order
{
   int* newArray = new int[s];
    
   int i;
   /*
   for (i=0;i<s;i++) 
     newArray[i] = a[s-1-i];
   */


   int j;
   j = s-1;
   for (i=0;i<s;i++) {
     newArray[i] = a[j];
     j--;
   }

/*
   int j;
   for (i=0,j=s-1;i<s;i++,j--) {
     newArray[i] = a[j];
   }
*/

   return newArray;
}

int* concatArrays(const int a1[], int s1, const int a2[], int s2)
// allocate new array of size s1+s2, copy elments from a1,
// then elements from a2

{
  int *newArray = new int[s1+s2];

  int i;
  for (i=0;i<s1;i++) newArray[i] = a1[i];

  for (i=0;i<s2;i++) newArray[s1+i] = a2[i];


  return newArray;

}


int main() 
{
   int a = 5;
   print (&a);
   print2(&a);

   int ar[] = {1,2,3,4};
   int *r = reverse(ar,4);
   int i;
   for (i = 0; i < 4; i++) cout << r[i] << " ";
   cout << endl;

   return 0;
}